A wire, which passes through the hole is a small bead, is bent in the form of quarter of a
circle. The wire is fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is
Text Solution
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Using conservation of energy: mg R (1- cosθ) = 
mv 2
Radial force Equation: mg cosθ– N = 
⇒ N = mg cosθ – 
= mg (3 cosθ–2)
Normal act radially outward on bead if cosθ > 
Normal radially inward on bead if cosθ < 
∴ Normal on ring is opposite to reaction on bead.
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